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11344043133 = 321260449237
BaseRepresentation
bin10101001000010100…
…00101110001111101
31002021120211002200200
422210022011301331
5141213033340013
65113354114113
7551054530023
oct124412056175
932246732620
1011344043133
1148a1464565
12224711b939
1310ba2a6377
1479886a713
15465d9ce73
hex2a4285c7d

11344043133 has 6 divisors (see below), whose sum is σ = 16385840094. Its totient is φ = 7562695416.

The previous prime is 11344043111. The next prime is 11344043167. The reversal of 11344043133 is 33134044311.

11344043133 is a `hidden beast` number, since 1 + 1 + 344 + 0 + 4 + 313 + 3 = 666.

It can be written as a sum of positive squares in only one way, i.e., 10535380164 + 808662969 = 102642^2 + 28437^2 .

It is not a de Polignac number, because 11344043133 - 210 = 11344042109 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11344043097 and 11344043106.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11344043173) by changing a digit.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 630224610 + ... + 630224627.

It is an arithmetic number, because the mean of its divisors is an integer number (2730973349).

Almost surely, 211344043133 is an apocalyptic number.

It is an amenable number.

11344043133 is a deficient number, since it is larger than the sum of its proper divisors (5041796961).

11344043133 is a wasteful number, since it uses less digits than its factorization.

11344043133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1260449243 (or 1260449240 counting only the distinct ones).

The product of its (nonzero) digits is 5184, while the sum is 27.

Adding to 11344043133 its reverse (33134044311), we get a palindrome (44478087444).

The spelling of 11344043133 in words is "eleven billion, three hundred forty-four million, forty-three thousand, one hundred thirty-three".

Divisors: 1 3 9 1260449237 3781347711 11344043133