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113441352013 = 1110312850183
BaseRepresentation
bin110100110100110100…
…0011010100101001101
3101211210220220202212001
41221221220122211031
53324311441231023
6124040401512301
711124116403463
oct1515150324515
9354726822761
10113441352013
114412375a890
1219b9b342691
13a90b470a82
1456c2276833
152e3e2bc6ad
hex1a69a1a94d

113441352013 has 4 divisors (see below), whose sum is σ = 123754202208. Its totient is φ = 103128501820.

The previous prime is 113441352001. The next prime is 113441352029. The reversal of 113441352013 is 310253144311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 113441352013 - 217 = 113441220941 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (113441382013) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5156425081 + ... + 5156425102.

It is an arithmetic number, because the mean of its divisors is an integer number (30938550552).

Almost surely, 2113441352013 is an apocalyptic number.

It is an amenable number.

113441352013 is a deficient number, since it is larger than the sum of its proper divisors (10312850195).

113441352013 is a wasteful number, since it uses less digits than its factorization.

113441352013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10312850194.

The product of its (nonzero) digits is 4320, while the sum is 28.

Adding to 113441352013 its reverse (310253144311), we get a palindrome (423694496324).

The spelling of 113441352013 in words is "one hundred thirteen billion, four hundred forty-one million, three hundred fifty-two thousand, thirteen".

Divisors: 1 11 10312850183 113441352013