Base | Representation |
---|---|
bin | 11001110010110100010011… |
… | …111010010001110000011001 |
3 | 112212200001222222211012221120 |
4 | 121302310103322101300121 |
5 | 104332123342114432213 |
6 | 1041135045052555453 |
7 | 32616002600215560 |
oct | 3162642372216031 |
9 | 485601888735846 |
10 | 113443305233433 |
11 | 3316804338608a |
12 | 108820a5482b89 |
13 | 4b3b8721b7376 |
14 | 2002984546bd7 |
15 | d1adc25c0423 |
hex | 672d13e91c19 |
113443305233433 has 32 divisors (see below), whose sum is σ = 178443441487872. Its totient is φ = 62733227630400.
The previous prime is 113443305233399. The next prime is 113443305233501. The reversal of 113443305233433 is 334332503344311.
It is not a de Polignac number, because 113443305233433 - 210 = 113443305232409 is a prime.
It is not an unprimeable number, because it can be changed into a prime (113443305233033) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 123800535 + ... + 124713507.
It is an arithmetic number, because the mean of its divisors is an integer number (5576357546496).
Almost surely, 2113443305233433 is an apocalyptic number.
It is an amenable number.
113443305233433 is a deficient number, since it is larger than the sum of its proper divisors (65000136254439).
113443305233433 is a wasteful number, since it uses less digits than its factorization.
113443305233433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1103885.
The product of its (nonzero) digits is 1399680, while the sum is 42.
Adding to 113443305233433 its reverse (334332503344311), we get a palindrome (447775808577744).
The spelling of 113443305233433 in words is "one hundred thirteen trillion, four hundred forty-three billion, three hundred five million, two hundred thirty-three thousand, four hundred thirty-three".
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