113444133533 has 4 divisors (see below), whose sum is σ = 113480861820. Its totient is φ = 113407405248.

The previous prime is 113444133527. The next prime is 113444133557. The reversal of 113444133533 is 335331444311.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 335331444311 = 1873 ⋅179034407.

It can be written as a sum of positive squares in 2 ways, for example, as 50356257604 + 63087875929 = 224402^2 + 251173^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-113444133533 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 113444133493 and 113444133502.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (113444133233) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18359510 + ... + 18365687.

It is an arithmetic number, because the mean of its divisors is an integer number (28370215455).

Almost surely, 2^113444133533 is an apocalyptic number.

It is an amenable number.

113444133533 is a deficient number, since it is larger than the sum of its proper divisors (36728287).

113444133533 is an equidigital number, since it uses as much as digits as its factorization.

113444133533 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 36728286.

The product of its digits is 77760, while the sum is 35.

Adding to 113444133533 its reverse (335331444311), we get a palindrome (448775577844).

The spelling of 113444133533 in words is "one hundred thirteen billion, four hundred forty-four million, one hundred thirty-three thousand, five hundred thirty-three".