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11350001441 = 88712795943
BaseRepresentation
bin10101001001000001…
…10100011100100001
31002022000000210221202
422210200310130201
5141221100021231
65114125530545
7551156264132
oct124440643441
932260023852
1011350001441
1148a4864089
122249113a55
1310bb5b13ac
1479957bc89
154666785cb
hex2a4834721

11350001441 has 4 divisors (see below), whose sum is σ = 11362798272. Its totient is φ = 11337204612.

The previous prime is 11350001419. The next prime is 11350001447. The reversal of 11350001441 is 14410005311.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11350001441 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11350001447) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6397085 + ... + 6398858.

It is an arithmetic number, because the mean of its divisors is an integer number (2840699568).

Almost surely, 211350001441 is an apocalyptic number.

It is an amenable number.

11350001441 is a deficient number, since it is larger than the sum of its proper divisors (12796831).

11350001441 is an equidigital number, since it uses as much as digits as its factorization.

11350001441 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12796830.

The product of its (nonzero) digits is 240, while the sum is 20.

Adding to 11350001441 its reverse (14410005311), we get a palindrome (25760006752).

The spelling of 11350001441 in words is "eleven billion, three hundred fifty million, one thousand, four hundred forty-one".

Divisors: 1 887 12795943 11350001441