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1135001125353 = 37127277195353
BaseRepresentation
bin10000100001000011010…
…101101100000111101001
311000111122011212011100210
4100201003111230013221
5122043440242002403
62225225021051333
7145000246245534
oct20410325540751
94014564764323
101135001125353
113a8395600577
12163b796b6b49
1383051304234
143cd11bc7a1b
151e7cd6a4b03
hex1084356c1e9

1135001125353 has 16 divisors (see below), whose sum is σ = 1534713526656. Its totient is φ = 745978961280.

The previous prime is 1135001125267. The next prime is 1135001125373. The reversal of 1135001125353 is 3535211005311.

It is a de Polignac number, because none of the positive numbers 2k-1135001125353 is a prime.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 1135001125353.

It is not an unprimeable number, because it can be changed into a prime (1135001125373) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 5712325 + ... + 5907677.

It is an arithmetic number, because the mean of its divisors is an integer number (95919595416).

Almost surely, 21135001125353 is an apocalyptic number.

It is an amenable number.

1135001125353 is a deficient number, since it is larger than the sum of its proper divisors (399712401303).

1135001125353 is a wasteful number, since it uses less digits than its factorization.

1135001125353 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 222704.

The product of its (nonzero) digits is 6750, while the sum is 30.

The spelling of 1135001125353 in words is "one trillion, one hundred thirty-five billion, one million, one hundred twenty-five thousand, three hundred fifty-three".

Divisors: 1 3 71 213 27277 81831 195353 586059 1936667 5810001 13870063 41610189 5328643781 15985931343 378333708451 1135001125353