Base | Representation |
---|---|
bin | 11001110011101001010011… |
… | …101110011110001000111111 |
3 | 112212212111212211000222221011 |
4 | 121303221103232132020333 |
5 | 104334041412334030403 |
6 | 1041221135445220051 |
7 | 32623056010504123 |
oct | 3163512356361077 |
9 | 485774784028834 |
10 | 113500210455103 |
11 | 3318a1949483aa |
12 | 10891126a01627 |
13 | 4b44040727174 |
14 | 2005621da1583 |
15 | d1c6032aba6d |
hex | 673a53b9e23f |
113500210455103 has 4 divisors (see below), whose sum is σ = 113501551373200. Its totient is φ = 113498869537008.
The previous prime is 113500210455101. The next prime is 113500210455119. The reversal of 113500210455103 is 301554012005311.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 113500210455103 - 21 = 113500210455101 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (113500210455101) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 670332075 + ... + 670501372.
It is an arithmetic number, because the mean of its divisors is an integer number (28375387843300).
Almost surely, 2113500210455103 is an apocalyptic number.
113500210455103 is a deficient number, since it is larger than the sum of its proper divisors (1340918097).
113500210455103 is an equidigital number, since it uses as much as digits as its factorization.
113500210455103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1340918096.
The product of its (nonzero) digits is 9000, while the sum is 31.
The spelling of 113500210455103 in words is "one hundred thirteen trillion, five hundred billion, two hundred ten million, four hundred fifty-five thousand, one hundred three".
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