Base | Representation |
---|---|
bin | 10000100001000101110… |
… | …111100010010010110001 |
3 | 11000111202010200200101010 |
4 | 100201011313202102301 |
5 | 122044032122134213 |
6 | 2225233134301133 |
7 | 145001303002620 |
oct | 20410567422261 |
9 | 4014663620333 |
10 | 1135043552433 |
11 | 3a840754967a |
12 | 163b8b9577a9 |
13 | 8305a03a70b |
14 | 3cd176ad6b7 |
15 | 1e7d2285ac3 |
hex | 10845de24b1 |
1135043552433 has 64 divisors (see below), whose sum is σ = 1866597433344. Its totient is φ = 599227200000.
The previous prime is 1135043552417. The next prime is 1135043552443. The reversal of 1135043552433 is 3342553405311.
It is not a de Polignac number, because 1135043552433 - 24 = 1135043552417 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1135043552391 and 1135043552400.
It is not an unprimeable number, because it can be changed into a prime (1135043552443) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 7728183 + ... + 7873683.
It is an arithmetic number, because the mean of its divisors is an integer number (29165584896).
Almost surely, 21135043552433 is an apocalyptic number.
It is an amenable number.
1135043552433 is a deficient number, since it is larger than the sum of its proper divisors (731553880911).
1135043552433 is a wasteful number, since it uses less digits than its factorization.
1135043552433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 146086.
The product of its (nonzero) digits is 324000, while the sum is 39.
Adding to 1135043552433 its reverse (3342553405311), we get a palindrome (4477596957744).
The spelling of 1135043552433 in words is "one trillion, one hundred thirty-five billion, forty-three million, five hundred fifty-two thousand, four hundred thirty-three".
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