Base | Representation |
---|---|
bin | 10101001001001011… |
… | …00110010001110101 |
3 | 1002022002101110022202 |
4 | 22210211212101311 |
5 | 141221410113013 |
6 | 5114212434245 |
7 | 551203032242 |
oct | 124445462165 |
9 | 32262343282 |
10 | 11351254133 |
11 | 48a553a26a |
12 | 2249618985 |
13 | 10bb92c62b |
14 | 7997c65c9 |
15 | 466824858 |
hex | 2a4966475 |
11351254133 has 4 divisors (see below), whose sum is σ = 11352575520. Its totient is φ = 11349932748.
The previous prime is 11351254129. The next prime is 11351254141. The reversal of 11351254133 is 33145215311.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 11351254133 - 22 = 11351254129 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 11351254096 and 11351254105.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11351257133) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 647723 + ... + 665016.
It is an arithmetic number, because the mean of its divisors is an integer number (2838143880).
Almost surely, 211351254133 is an apocalyptic number.
It is an amenable number.
11351254133 is a deficient number, since it is larger than the sum of its proper divisors (1321387).
11351254133 is an equidigital number, since it uses as much as digits as its factorization.
11351254133 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1321386.
The product of its digits is 5400, while the sum is 29.
Adding to 11351254133 its reverse (33145215311), we get a palindrome (44496469444).
The spelling of 11351254133 in words is "eleven billion, three hundred fifty-one million, two hundred fifty-four thousand, one hundred thirty-three".
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