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113540000550115 = 559384881357797
BaseRepresentation
bin11001110100001110010111…
…011001101000110011100011
3112220000022120212010020220211
4121310032113121220303203
5104340214410120100430
61041251320045114551
732625665025645046
oct3164162731506343
9486008525106824
10113540000550115
11331a5053368747
1210898990558a57
134b47a12164b99
14200751872cc5d
15d1d68162e72a
hex674397668ce3

113540000550115 has 8 divisors (see below), whose sum is σ = 138557288807280. Its totient is φ = 89292475008672.

The previous prime is 113540000550091. The next prime is 113540000550143. The reversal of 113540000550115 is 511055000045311.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 113540000550115 - 213 = 113540000541923 is a prime.

It is a super-2 number, since 2×1135400005501152 (a number of 29 digits) contains 22 as substring.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 192440678604 + ... + 192440679193.

It is an arithmetic number, because the mean of its divisors is an integer number (17319661100910).

Almost surely, 2113540000550115 is an apocalyptic number.

113540000550115 is a deficient number, since it is larger than the sum of its proper divisors (25017288257165).

113540000550115 is an equidigital number, since it uses as much as digits as its factorization.

113540000550115 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 384881357861.

The product of its (nonzero) digits is 7500, while the sum is 31.

Adding to 113540000550115 its reverse (511055000045311), we get a palindrome (624595000595426).

The spelling of 113540000550115 in words is "one hundred thirteen trillion, five hundred forty billion, five hundred fifty thousand, one hundred fifteen".

Divisors: 1 5 59 295 384881357797 1924406788985 22708000110023 113540000550115