113540401504053 has 6 divisors (see below), whose sum is σ = 164002802172534. Its totient is φ = 75693601002696.

The previous prime is 113540401504051. The next prime is 113540401504121. The reversal of 113540401504053 is 350405104045311.

113540401504053 is a `hidden beast` number, since 1 + 13 + 5 + 404 + 0 + 150 + 40 + 53 = 666.

It can be written as a sum of positive squares in only one way, i.e., 57709288735569 + 55831112768484 = 7596663^2 + 7472022^2 .

It is not a de Polignac number, because 113540401504053 - 2¹ = 113540401504051 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 113540401503999 and 113540401504017.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (113540401504051) by changing a digit.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 6307800083550 + ... + 6307800083567.

It is an arithmetic number, because the mean of its divisors is an integer number (27333800362089).

Almost surely, 2^{113540401504053} is an apocalyptic number.

It is an amenable number.

113540401504053 is a deficient number, since it is larger than the sum of its proper divisors (50462400668481).

113540401504053 is a wasteful number, since it uses less digits than its factorization.

113540401504053 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12615600167123 (or 12615600167120 counting only the distinct ones).

The product of its (nonzero) digits is 72000, while the sum is 36.

Adding to 113540401504053 its reverse (350405104045311), we get a palindrome (463945505549364).

The spelling of 113540401504053 in words is "one hundred thirteen trillion, five hundred forty billion, four hundred one million, five hundred four thousand, fifty-three".