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11354333345311 = 111032212122301
BaseRepresentation
bin1010010100111010001100…
…0000010111011000011111
31111012110112000100121221011
42211032203000113120133
52442012133314022221
640052035252520051
72251215652005355
oct245164300273037
944173460317834
1011354333345311
113688389191780
121334667320027
1364492a9b8718
142b37a47317d5
1514a543d7c1e1
hexa53a301761f

11354333345311 has 4 divisors (see below), whose sum is σ = 12386545467624. Its totient is φ = 10322121223000.

The previous prime is 11354333345293. The next prime is 11354333345489.

11354333345311 is nontrivially palindromic in base 10.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 11354333345311 - 217 = 11354333214239 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11354333345111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 516106061140 + ... + 516106061161.

It is an arithmetic number, because the mean of its divisors is an integer number (3096636366906).

Almost surely, 211354333345311 is an apocalyptic number.

11354333345311 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

11354333345311 is a deficient number, since it is larger than the sum of its proper divisors (1032212122313).

11354333345311 is a wasteful number, since it uses less digits than its factorization.

11354333345311 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1032212122312.

The product of its digits is 291600, while the sum is 40.

The spelling of 11354333345311 in words is "eleven trillion, three hundred fifty-four billion, three hundred thirty-three million, three hundred forty-five thousand, three hundred eleven".

Divisors: 1 11 1032212122301 11354333345311