Base | Representation |
---|---|
bin | 10101001001101000… |
… | …00110010010010101 |
3 | 1002022100112120110222 |
4 | 22210310012102111 |
5 | 141223343232003 |
6 | 5114430124125 |
7 | 551250243233 |
oct | 124464062225 |
9 | 32270476428 |
10 | 11355055253 |
11 | 48a76a6093 |
12 | 224a950645 |
13 | 10bc660809 |
14 | 79a0d5953 |
15 | 466d25c38 |
hex | 2a4d06495 |
11355055253 has 4 divisors (see below), whose sum is σ = 11952689760. Its totient is φ = 10757420748.
The previous prime is 11355055249. The next prime is 11355055289. The reversal of 11355055253 is 35255055311.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 11355055253 - 22 = 11355055249 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11355055213) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 298817225 + ... + 298817262.
It is an arithmetic number, because the mean of its divisors is an integer number (2988172440).
Almost surely, 211355055253 is an apocalyptic number.
It is an amenable number.
11355055253 is a deficient number, since it is larger than the sum of its proper divisors (597634507).
11355055253 is an equidigital number, since it uses as much as digits as its factorization.
11355055253 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 597634506.
The product of its (nonzero) digits is 56250, while the sum is 35.
The spelling of 11355055253 in words is "eleven billion, three hundred fifty-five million, fifty-five thousand, two hundred fifty-three".
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