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113552144551 = 647175505633
BaseRepresentation
bin110100111000000111…
…1000011100010100111
3101212002122101121122101
41221300033003202213
53330023322111201
6124055400312531
711126633206006
oct1516017034247
9355078347571
10113552144551
114418025296a
121a010472747
13a9283c2aa1
1456d2c76c3d
152e48da4d01
hex1a703c38a7

113552144551 has 4 divisors (see below), whose sum is σ = 113727650832. Its totient is φ = 113376638272.

The previous prime is 113552144543. The next prime is 113552144557. The reversal of 113552144551 is 155441255311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 113552144551 - 23 = 113552144543 is a prime.

It is a super-4 number, since 4×1135521445514 (a number of 45 digits) contains 4444 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 113552144551.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (113552144557) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 87752170 + ... + 87753463.

It is an arithmetic number, because the mean of its divisors is an integer number (28431912708).

Almost surely, 2113552144551 is an apocalyptic number.

113552144551 is a deficient number, since it is larger than the sum of its proper divisors (175506281).

113552144551 is an equidigital number, since it uses as much as digits as its factorization.

113552144551 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 175506280.

The product of its digits is 60000, while the sum is 37.

Adding to 113552144551 its reverse (155441255311), we get a palindrome (268993399862).

The spelling of 113552144551 in words is "one hundred thirteen billion, five hundred fifty-two million, one hundred forty-four thousand, five hundred fifty-one".

Divisors: 1 647 175505633 113552144551