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11355243135261 = 33785081045087
BaseRepresentation
bin1010010100111101100100…
…1110111100000100011101
31111012112212102021202010020
42211033121032330010131
52442021014220312021
640052305432502353
72251250340050244
oct245173116740435
944175772252106
1011355243135261
1136888057a03a3
12133487bb4a9b9
13644a4432c17c
142b384d4b995b
1514a598b8e7c6
hexa53d93bc11d

11355243135261 has 4 divisors (see below), whose sum is σ = 15140324180352. Its totient is φ = 7570162090172.

The previous prime is 11355243135259. The next prime is 11355243135289. The reversal of 11355243135261 is 16253134255311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11355243135261 - 21 = 11355243135259 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11355243135251) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1892540522541 + ... + 1892540522546.

It is an arithmetic number, because the mean of its divisors is an integer number (3785081045088).

Almost surely, 211355243135261 is an apocalyptic number.

It is an amenable number.

11355243135261 is a deficient number, since it is larger than the sum of its proper divisors (3785081045091).

11355243135261 is an equidigital number, since it uses as much as digits as its factorization.

11355243135261 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3785081045090.

The product of its digits is 324000, while the sum is 42.

The spelling of 11355243135261 in words is "eleven trillion, three hundred fifty-five billion, two hundred forty-three million, one hundred thirty-five thousand, two hundred sixty-one".

Divisors: 1 3 3785081045087 11355243135261