113553455040343 has 4 divisors (see below), whose sum is σ = 113553495538560. Its totient is φ = 113553414542128.

The previous prime is 113553455040287. The next prime is 113553455040353. The reversal of 113553455040343 is 343040554355311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 113553455040343 - 2³⁷ = 113416016086871 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 113553455040293 and 113553455040302.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (113553455040353) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15703030 + ... + 21764467.

It is an arithmetic number, because the mean of its divisors is an integer number (28388373884640).

Almost surely, 2^{113553455040343} is an apocalyptic number.

113553455040343 is a deficient number, since it is larger than the sum of its proper divisors (40498217).

113553455040343 is an equidigital number, since it uses as much as digits as its factorization.

113553455040343 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 40498216.

The product of its (nonzero) digits is 3240000, while the sum is 46.

The spelling of 113553455040343 in words is "one hundred thirteen trillion, five hundred fifty-three billion, four hundred fifty-five million, forty thousand, three hundred forty-three".