Base | Representation |
---|---|
bin | 11001110100011010111101… |
… | …111100100110010101100101 |
3 | 112220001121111220012210220012 |
4 | 121310122331330212111211 |
5 | 104340430113212314031 |
6 | 1041301434510220005 |
7 | 32626654245443645 |
oct | 3164327574462545 |
9 | 486047456183805 |
10 | 113553532151141 |
11 | 331aa867623895 |
12 | 1089b5281b4605 |
13 | 4b4908a7045b4 |
14 | 200803d918525 |
15 | d1dbc458cb2b |
hex | 6746bdf26565 |
113553532151141 has 4 divisors (see below), whose sum is σ = 113553832444800. Its totient is φ = 113553231857484.
The previous prime is 113553532151099. The next prime is 113553532151209. The reversal of 113553532151141 is 141151235355311.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-113553532151141 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (113553532151041) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 149578901 + ... + 150336138.
It is an arithmetic number, because the mean of its divisors is an integer number (28388458111200).
Almost surely, 2113553532151141 is an apocalyptic number.
It is an amenable number.
113553532151141 is a deficient number, since it is larger than the sum of its proper divisors (300293659).
113553532151141 is an equidigital number, since it uses as much as digits as its factorization.
113553532151141 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 300293658.
The product of its digits is 135000, while the sum is 41.
The spelling of 113553532151141 in words is "one hundred thirteen trillion, five hundred fifty-three billion, five hundred thirty-two million, one hundred fifty-one thousand, one hundred forty-one".
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