Base | Representation |
---|---|
bin | 11001110100011011110100… |
… | …111110101010111010010101 |
3 | 112220001200220020112210112120 |
4 | 121310123310332222322111 |
5 | 104340434011043103140 |
6 | 1041302110251410153 |
7 | 32630016156333153 |
oct | 3164336476527225 |
9 | 486050806483476 |
10 | 113554455441045 |
11 | 332001a08131a3 |
12 | 1089b745453959 |
13 | 4b491a6a93998 |
14 | 20080ca3b83d3 |
15 | d1dc2a66a1d0 |
hex | 6746f4faae95 |
113554455441045 has 16 divisors (see below), whose sum is σ = 181694402900160. Its totient is φ = 60559951503744.
The previous prime is 113554455440983. The next prime is 113554455441073. The reversal of 113554455441045 is 540144554455311.
It is not a de Polignac number, because 113554455441045 - 216 = 113554455375509 is a prime.
It is a super-2 number, since 2×1135544554410452 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 151158544 + ... + 151907913.
It is an arithmetic number, because the mean of its divisors is an integer number (11355900181260).
Almost surely, 2113554455441045 is an apocalyptic number.
113554455441045 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
113554455441045 is a deficient number, since it is larger than the sum of its proper divisors (68139947459115).
113554455441045 is a wasteful number, since it uses less digits than its factorization.
113554455441045 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 303091444.
The product of its (nonzero) digits is 9600000, while the sum is 51.
The spelling of 113554455441045 in words is "one hundred thirteen trillion, five hundred fifty-four billion, four hundred fifty-five million, four hundred forty-one thousand, forty-five".
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