Base | Representation |
---|---|
bin | 110100111000010110… |
… | …1100100010100001011 |
3 | 101212010012102222121111 |
4 | 1221300231210110023 |
5 | 3330032344034430 |
6 | 124100243551151 |
7 | 11130061201306 |
oct | 1516055442413 |
9 | 355105388544 |
10 | 113560143115 |
11 | 44184816351 |
12 | 1a01308b4b7 |
13 | a929c63673 |
14 | 56d3d59b3d |
15 | 2e49934c2a |
hex | 1a70b6450b |
113560143115 has 8 divisors (see below), whose sum is σ = 136388551248. Its totient is φ = 90770528160.
The previous prime is 113560143071. The next prime is 113560143131. The reversal of 113560143115 is 511341065311.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 113560143115 - 225 = 113526588683 is a prime.
It is a super-2 number, since 2×1135601431152 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 9691852 + ... + 9703561.
It is an arithmetic number, because the mean of its divisors is an integer number (17048568906).
Almost surely, 2113560143115 is an apocalyptic number.
113560143115 is a deficient number, since it is larger than the sum of its proper divisors (22828408133).
113560143115 is a wasteful number, since it uses less digits than its factorization.
113560143115 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 19396589.
The product of its (nonzero) digits is 5400, while the sum is 31.
The spelling of 113560143115 in words is "one hundred thirteen billion, five hundred sixty million, one hundred forty-three thousand, one hundred fifteen".
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