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113560143131 is a prime number
BaseRepresentation
bin110100111000010110…
…1100100010100011011
3101212010012102222122002
41221300231210110123
53330032344040011
6124100243551215
711130061201331
oct1516055442433
9355105388562
10113560143131
1144184816366
121a01308b50b
13a929c63686
1456d3d59b51
152e49934c3b
hex1a70b6451b

113560143131 has 2 divisors, whose sum is σ = 113560143132. Its totient is φ = 113560143130.

The previous prime is 113560143071. The next prime is 113560143139. The reversal of 113560143131 is 131341065311.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 113560143131 - 214 = 113560126747 is a prime.

It is a super-2 number, since 2×1135601431312 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 113560143094 and 113560143103.

It is not a weakly prime, because it can be changed into another prime (113560143139) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56780071565 + 56780071566.

It is an arithmetic number, because the mean of its divisors is an integer number (56780071566).

Almost surely, 2113560143131 is an apocalyptic number.

113560143131 is a deficient number, since it is larger than the sum of its proper divisors (1).

113560143131 is an equidigital number, since it uses as much as digits as its factorization.

113560143131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3240, while the sum is 29.

The spelling of 113560143131 in words is "one hundred thirteen billion, five hundred sixty million, one hundred forty-three thousand, one hundred thirty-one".