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113577913457 = 179634513483
BaseRepresentation
bin110100111000111000…
…1010110110001110001
3101212011102212210221022
41221301301112301301
53330101421212312
6124102120505225
711130365223011
oct1516161266161
9355142783838
10113577913457
1144193853488
121a01901b215
13a930845c68
1456d6463c41
152e4b295172
hex1a71c56c71

113577913457 has 4 divisors (see below), whose sum is σ = 114212427120. Its totient is φ = 112943399796.

The previous prime is 113577913387. The next prime is 113577913481. The reversal of 113577913457 is 754319775311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 113577913457 - 220 = 113576864881 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 113577913399 and 113577913408.

It is not an unprimeable number, because it can be changed into a prime (113577916457) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 317256563 + ... + 317256920.

It is an arithmetic number, because the mean of its divisors is an integer number (28553106780).

Almost surely, 2113577913457 is an apocalyptic number.

It is an amenable number.

113577913457 is a deficient number, since it is larger than the sum of its proper divisors (634513663).

113577913457 is an equidigital number, since it uses as much as digits as its factorization.

113577913457 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 634513662.

The product of its digits is 2778300, while the sum is 53.

The spelling of 113577913457 in words is "one hundred thirteen billion, five hundred seventy-seven million, nine hundred thirteen thousand, four hundred fifty-seven".

Divisors: 1 179 634513483 113577913457