Base | Representation |
---|---|
bin | 10000100010000010101… |
… | …101100000110010011111 |
3 | 11000121101021110210211010 |
4 | 100202002231200302133 |
5 | 122103124432210012 |
6 | 2225522321230303 |
7 | 145035506342250 |
oct | 20420255406237 |
9 | 4017337423733 |
10 | 1136064335007 |
11 | 3a8890777738 |
12 | 164215792393 |
13 | 83190673284 |
14 | 3cdb30aab27 |
15 | 1e841bbec3c |
hex | 10882b60c9f |
1136064335007 has 16 divisors (see below), whose sum is σ = 1731402982400. Its totient is φ = 649083121632.
The previous prime is 1136064334987. The next prime is 1136064335027. The reversal of 1136064335007 is 7005334606311.
It is an interprime number because it is at equal distance from previous prime (1136064334987) and next prime (1136064335027).
It is not a de Polignac number, because 1136064335007 - 28 = 1136064334751 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1136064335027) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3876007 + ... + 4158792.
It is an arithmetic number, because the mean of its divisors is an integer number (108212686400).
Almost surely, 21136064335007 is an apocalyptic number.
1136064335007 is a deficient number, since it is larger than the sum of its proper divisors (595338647393).
1136064335007 is an equidigital number, since it uses as much as digits as its factorization.
1136064335007 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 8041542.
The product of its (nonzero) digits is 136080, while the sum is 39.
The spelling of 1136064335007 in words is "one trillion, one hundred thirty-six billion, sixty-four million, three hundred thirty-five thousand, seven".
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