1136414117 has 4 divisors (see below), whose sum is σ = 1138692000. Its totient is φ = 1134136236.

The previous prime is 1136414093. The next prime is 1136414137. The reversal of 1136414117 is 7114146311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1136414117 - 2³⁰ = 62672293 is a prime.

It is a super-3 number, since 3×1136414117³ (a number of 28 digits) contains 333 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1136414117.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1136414137) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1138193 + ... + 1139190.

It is an arithmetic number, because the mean of its divisors is an integer number (284673000).

Almost surely, 2^1136414117 is an apocalyptic number.

It is an amenable number.

1136414117 is a deficient number, since it is larger than the sum of its proper divisors (2277883).

1136414117 is an equidigital number, since it uses as much as digits as its factorization.

1136414117 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2277882.

The product of its digits is 2016, while the sum is 29.

The square root of 1136414117 is about 33710.7418636849. The cubic root of 1136414117 is about 1043.5474632431.

The spelling of 1136414117 in words is "one billion, one hundred thirty-six million, four hundred fourteen thousand, one hundred seventeen".