Base | Representation |
---|---|
bin | 10101001010110101… |
… | …10110001101001101 |
3 | 1002100001122122022000 |
4 | 22211122312031031 |
5 | 141233443304010 |
6 | 5115431542513 |
7 | 551432500536 |
oct | 124532661515 |
9 | 32301578260 |
10 | 11365213005 |
11 | 4902403823 |
12 | 225222aa39 |
13 | 10c17a9113 |
14 | 79b5bb68d |
15 | 467b807c0 |
hex | 2a56b634d |
11365213005 has 16 divisors (see below), whose sum is σ = 20204823360. Its totient is φ = 6061446864.
The previous prime is 11365213001. The next prime is 11365213007. The reversal of 11365213005 is 50031256311.
11365213005 is a `hidden beast` number, since 1 + 1 + 3 + 652 + 1 + 3 + 0 + 0 + 5 = 666.
It is not a de Polignac number, because 11365213005 - 22 = 11365213001 is a prime.
It is a super-2 number, since 2×113652130052 (a number of 21 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (27).
It is a self number, because there is not a number n which added to its sum of digits gives 11365213005.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11365213001) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 42093247 + ... + 42093516.
It is an arithmetic number, because the mean of its divisors is an integer number (1262801460).
Almost surely, 211365213005 is an apocalyptic number.
11365213005 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
11365213005 is a deficient number, since it is larger than the sum of its proper divisors (8839610355).
11365213005 is an equidigital number, since it uses as much as digits as its factorization.
11365213005 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 84186777 (or 84186771 counting only the distinct ones).
The product of its (nonzero) digits is 2700, while the sum is 27.
Adding to 11365213005 its reverse (50031256311), we get a palindrome (61396469316).
The spelling of 11365213005 in words is "eleven billion, three hundred sixty-five million, two hundred thirteen thousand, five".
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