Base | Representation |
---|---|
bin | 10000100010100010101… |
… | …101001110010010011101 |
3 | 11000122202200112211022101 |
4 | 100202202231032102131 |
5 | 122110224342131031 |
6 | 2230051454445101 |
7 | 145055015125531 |
oct | 20424255162235 |
9 | 4018680484271 |
10 | 1136601130141 |
11 | 3a9036785884 |
12 | 164345503791 |
13 | 8324793c229 |
14 | 3d0244bdbc1 |
15 | 1e873da5361 |
hex | 108a2b4e49d |
1136601130141 has 4 divisors (see below), whose sum is σ = 1136792902752. Its totient is φ = 1136409357532.
The previous prime is 1136601130127. The next prime is 1136601130157. The reversal of 1136601130141 is 1410311066311.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 1136601130141 - 231 = 1134453646493 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1136601130541) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 95877415 + ... + 95889268.
It is an arithmetic number, because the mean of its divisors is an integer number (284198225688).
Almost surely, 21136601130141 is an apocalyptic number.
It is an amenable number.
1136601130141 is a deficient number, since it is larger than the sum of its proper divisors (191772611).
1136601130141 is an equidigital number, since it uses as much as digits as its factorization.
1136601130141 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 191772610.
The product of its (nonzero) digits is 1296, while the sum is 28.
Adding to 1136601130141 its reverse (1410311066311), we get a palindrome (2546912196452).
The spelling of 1136601130141 in words is "one trillion, one hundred thirty-six billion, six hundred one million, one hundred thirty thousand, one hundred forty-one".
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