Base | Representation |
---|---|
bin | 11001110101111110101100… |
… | …011110000101010001011011 |
3 | 112220102211220112221200212002 |
4 | 121311332230132011101123 |
5 | 104344203413424333430 |
6 | 1041422544223111215 |
7 | 32640464643614534 |
oct | 3165765436052133 |
9 | 486384815850762 |
10 | 113660613121115 |
11 | 33241216a87495 |
12 | 108b823144250b |
13 | 4b561c42299a8 |
14 | 200d2bb17168b |
15 | d21890287845 |
hex | 675fac78545b |
113660613121115 has 8 divisors (see below), whose sum is σ = 141095933529840. Its totient is φ = 87793025307232.
The previous prime is 113660613121087. The next prime is 113660613121117. The reversal of 113660613121115 is 511121316066311.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 113660613121115 - 222 = 113660608926811 is a prime.
It is not an unprimeable number, because it can be changed into a prime (113660613121117) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 391933148549 + ... + 391933148838.
It is an arithmetic number, because the mean of its divisors is an integer number (17636991691230).
Almost surely, 2113660613121115 is an apocalyptic number.
113660613121115 is a deficient number, since it is larger than the sum of its proper divisors (27435320408725).
113660613121115 is an equidigital number, since it uses as much as digits as its factorization.
113660613121115 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 783866297421.
The product of its (nonzero) digits is 19440, while the sum is 38.
Adding to 113660613121115 its reverse (511121316066311), we get a palindrome (624781929187426).
The spelling of 113660613121115 in words is "one hundred thirteen trillion, six hundred sixty billion, six hundred thirteen million, one hundred twenty-one thousand, one hundred fifteen".
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