113701633230135 has 16 divisors (see below), whose sum is σ = 181922793744384. Its totient is φ = 60640810864032.

The previous prime is 113701633230103. The next prime is 113701633230169. The reversal of 113701633230135 is 531032336107311.

It is not a de Polignac number, because 113701633230135 - 2⁵ = 113701633230103 is a prime.

It is a super-2 number, since 2×113701633230135² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 113701633230093 and 113701633230102.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 14811694 + ... + 21137396.

It is an arithmetic number, because the mean of its divisors is an integer number (11370174609024).

Almost surely, 2^{113701633230135} is an apocalyptic number.

113701633230135 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

113701633230135 is a deficient number, since it is larger than the sum of its proper divisors (68221160514249).

113701633230135 is a wasteful number, since it uses less digits than its factorization.

113701633230135 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7524014.

The product of its (nonzero) digits is 102060, while the sum is 39.

Adding to 113701633230135 its reverse (531032336107311), we get a palindrome (644733969337446).

The spelling of 113701633230135 in words is "one hundred thirteen trillion, seven hundred one billion, six hundred thirty-three million, two hundred thirty thousand, one hundred thirty-five".