Base | Representation |
---|---|
bin | 1010010110100111100101… |
… | …0001110100100010000001 |
3 | 1111022021022111020010210221 |
4 | 2211221321101310202001 |
5 | 2443002303200033103 |
6 | 40113333152223041 |
7 | 2253305435611003 |
oct | 245517121644201 |
9 | 44267274203727 |
10 | 11383698049153 |
11 | 369988785a361 |
12 | 133a2a153aa81 |
13 | 64762a577421 |
14 | 2b4d8c646373 |
15 | 14b1b1d151bd |
hex | a5a79474881 |
11383698049153 has 16 divisors (see below), whose sum is σ = 12690571544640. Its totient is φ = 10147883558400.
The previous prime is 11383698049123. The next prime is 11383698049177. The reversal of 11383698049153 is 35194089638311.
It is a happy number.
It is a cyclic number.
It is not a de Polignac number, because 11383698049153 - 213 = 11383698040961 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 11383698049091 and 11383698049100.
It is not an unprimeable number, because it can be changed into a prime (11383698049123) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2533543 + ... + 5402428.
It is an arithmetic number, because the mean of its divisors is an integer number (793160721540).
Almost surely, 211383698049153 is an apocalyptic number.
It is an amenable number.
11383698049153 is a deficient number, since it is larger than the sum of its proper divisors (1306873495487).
11383698049153 is a wasteful number, since it uses less digits than its factorization.
11383698049153 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7940448.
The product of its (nonzero) digits is 16796160, while the sum is 61.
The spelling of 11383698049153 in words is "eleven trillion, three hundred eighty-three billion, six hundred ninety-eight million, forty-nine thousand, one hundred fifty-three".
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