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11385259135 = 5191009911867
BaseRepresentation
bin10101001101001110…
…10100010001111111
31002101110101002102021
422212213110101333
5141304111243020
65121425341011
7552065051215
oct124647242177
932343332367
1011385259135
114912755778
122258a97767
1310c59a7533
147a0118cb5
154697e01aa
hex2a69d447f

11385259135 has 16 divisors (see below), whose sum is σ = 14384016000. Its totient is φ = 8627246496.

The previous prime is 11385259111. The next prime is 11385259157. The reversal of 11385259135 is 53195258311.

It is a cyclic number.

It is not a de Polignac number, because 11385259135 - 25 = 11385259103 is a prime.

It is a super-2 number, since 2×113852591352 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11385259091 and 11385259100.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 953472 + ... + 965338.

It is an arithmetic number, because the mean of its divisors is an integer number (899001000).

Almost surely, 211385259135 is an apocalyptic number.

11385259135 is a deficient number, since it is larger than the sum of its proper divisors (2998756865).

11385259135 is a wasteful number, since it uses less digits than its factorization.

11385259135 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 21990.

The product of its digits is 162000, while the sum is 43.

The spelling of 11385259135 in words is "eleven billion, three hundred eighty-five million, two hundred fifty-nine thousand, one hundred thirty-five".

Divisors: 1 5 19 95 10099 11867 50495 59335 191881 225473 959405 1127365 119844833 599224165 2277051827 11385259135