Base | Representation |
---|---|
bin | 10101001101100011… |
… | …10001101011100001 |
3 | 1002101122112101112120 |
4 | 22212301301223201 |
5 | 141310312012433 |
6 | 5122004214453 |
7 | 552130261035 |
oct | 124661615341 |
9 | 32348471476 |
10 | 11388000993 |
11 | 4914258776 |
12 | 225999a429 |
13 | 10c6427535 |
14 | 7a06301c5 |
15 | 469b827b3 |
hex | 2a6c71ae1 |
11388000993 has 4 divisors (see below), whose sum is σ = 15184001328. Its totient is φ = 7592000660.
The previous prime is 11388000991. The next prime is 11388000997. The reversal of 11388000993 is 39900088311.
It is a happy number.
11388000993 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 11388000993 - 21 = 11388000991 is a prime.
It is not an unprimeable number, because it can be changed into a prime (11388000991) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1898000163 + ... + 1898000168.
It is an arithmetic number, because the mean of its divisors is an integer number (3796000332).
Almost surely, 211388000993 is an apocalyptic number.
It is an amenable number.
11388000993 is a deficient number, since it is larger than the sum of its proper divisors (3796000335).
11388000993 is an equidigital number, since it uses as much as digits as its factorization.
11388000993 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3796000334.
The product of its (nonzero) digits is 46656, while the sum is 42.
The spelling of 11388000993 in words is "eleven billion, three hundred eighty-eight million, nine hundred ninety-three", and thus it is an aban number.
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