Base | Representation |
---|---|
bin | 110101000100010110… |
… | …0011110010010001111 |
3 | 101220011020120022110112 |
4 | 1222020230132102033 |
5 | 3331343400300310 |
6 | 124204220030235 |
7 | 11143045230104 |
oct | 1521054362217 |
9 | 356136508415 |
10 | 113962509455 |
11 | 44370958113 |
12 | 1a10599237b |
13 | a992423062 |
14 | 5731578aab |
15 | 2e6ee14705 |
hex | 1a88b1e48f |
113962509455 has 4 divisors (see below), whose sum is σ = 136755011352. Its totient is φ = 91170007560.
The previous prime is 113962509443. The next prime is 113962509467. The reversal of 113962509455 is 554905269311.
It is a semiprime because it is the product of two primes.
It is an interprime number because it is at equal distance from previous prime (113962509443) and next prime (113962509467).
It is not a de Polignac number, because 113962509455 - 24 = 113962509439 is a prime.
It is a super-2 number, since 2×1139625094552 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11396250941 + ... + 11396250950.
It is an arithmetic number, because the mean of its divisors is an integer number (34188752838).
Almost surely, 2113962509455 is an apocalyptic number.
113962509455 is a deficient number, since it is larger than the sum of its proper divisors (22792501897).
113962509455 is an equidigital number, since it uses as much as digits as its factorization.
113962509455 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 22792501896.
The product of its (nonzero) digits is 1458000, while the sum is 50.
The spelling of 113962509455 in words is "one hundred thirteen billion, nine hundred sixty-two million, five hundred nine thousand, four hundred fifty-five".
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