Base | Representation |
---|---|
bin | 10000100101101101010… |
… | …011000011000110101011 |
3 | 11000222112120012111210221 |
4 | 100211231103003012223 |
5 | 122134210002342220 |
6 | 2231413033150511 |
7 | 145235156325661 |
oct | 20455523030653 |
9 | 4028476174727 |
10 | 1140000043435 |
11 | 3aa520339730 |
12 | 164b3385b437 |
13 | 83669b74526 |
14 | 3d267a86c31 |
15 | 1e9c24959aa |
hex | 1096d4c31ab |
1140000043435 has 16 divisors (see below), whose sum is σ = 1494548755200. Its totient is φ = 827877017440.
The previous prime is 1140000043397. The next prime is 1140000043439. The reversal of 1140000043435 is 5343400000411.
It is not a de Polignac number, because 1140000043435 - 231 = 1137852559787 is a prime.
It is a super-3 number, since 3×11400000434353 (a number of 37 digits) contains 333 as substring.
It is not an unprimeable number, because it can be changed into a prime (1140000043439) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 15136135 + ... + 15211264.
It is an arithmetic number, because the mean of its divisors is an integer number (93409297200).
Almost surely, 21140000043435 is an apocalyptic number.
1140000043435 is a deficient number, since it is larger than the sum of its proper divisors (354548711765).
1140000043435 is a wasteful number, since it uses less digits than its factorization.
1140000043435 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 30348098.
The product of its (nonzero) digits is 2880, while the sum is 25.
Adding to 1140000043435 its reverse (5343400000411), we get a palindrome (6483400043846).
The spelling of 1140000043435 in words is "one trillion, one hundred forty billion, forty-three thousand, four hundred thirty-five".
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