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1140000043435 = 51168330347399
BaseRepresentation
bin10000100101101101010…
…011000011000110101011
311000222112120012111210221
4100211231103003012223
5122134210002342220
62231413033150511
7145235156325661
oct20455523030653
94028476174727
101140000043435
113aa520339730
12164b3385b437
1383669b74526
143d267a86c31
151e9c24959aa
hex1096d4c31ab

1140000043435 has 16 divisors (see below), whose sum is σ = 1494548755200. Its totient is φ = 827877017440.

The previous prime is 1140000043397. The next prime is 1140000043439. The reversal of 1140000043435 is 5343400000411.

It is not a de Polignac number, because 1140000043435 - 231 = 1137852559787 is a prime.

It is a super-3 number, since 3×11400000434353 (a number of 37 digits) contains 333 as substring.

It is not an unprimeable number, because it can be changed into a prime (1140000043439) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 15136135 + ... + 15211264.

It is an arithmetic number, because the mean of its divisors is an integer number (93409297200).

Almost surely, 21140000043435 is an apocalyptic number.

1140000043435 is a deficient number, since it is larger than the sum of its proper divisors (354548711765).

1140000043435 is a wasteful number, since it uses less digits than its factorization.

1140000043435 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 30348098.

The product of its (nonzero) digits is 2880, while the sum is 25.

Adding to 1140000043435 its reverse (5343400000411), we get a palindrome (6483400043846).

The spelling of 1140000043435 in words is "one trillion, one hundred forty billion, forty-three thousand, four hundred thirty-five".

Divisors: 1 5 11 55 683 3415 7513 37565 30347399 151736995 333821389 1669106945 20727273517 103636367585 228000008687 1140000043435