11400110313002 has 4 divisors (see below), whose sum is σ = 17100165469506. Its totient is φ = 5700055156500.

The previous prime is 11400110313001. The next prime is 11400110313079. The reversal of 11400110313002 is 20031301100411.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 7828082132641 + 3572028180361 = 2797871^2 + 1889981^2 .

It is a super-2 number, since 2×11400110313002² (a number of 27 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (11400110313001) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2850027578249 + ... + 2850027578252.

Almost surely, 2^{11400110313002} is an apocalyptic number.

11400110313002 is a deficient number, since it is larger than the sum of its proper divisors (5700055156504).

11400110313002 is an equidigital number, since it uses as much as digits as its factorization.

11400110313002 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5700055156503.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 11400110313002 its reverse (20031301100411), we get a palindrome (31431411413413).

The spelling of 11400110313002 in words is "eleven trillion, four hundred billion, one hundred ten million, three hundred thirteen thousand, two".