Search a number
-
+
11400113 = 19957287
BaseRepresentation
bin101011011111…
…001110110001
3210110012000102
4223133032301
510404300423
61044202145
7165620324
oct53371661
923405012
1011400113
11648708a
123999355
132491c3a
14172a7bb
151002c28
hexadf3b1

11400113 has 4 divisors (see below), whose sum is σ = 11457600. Its totient is φ = 11342628.

The previous prime is 11400097. The next prime is 11400131. The reversal of 11400113 is 31100411.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11400113 - 24 = 11400097 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11400094 and 11400103.

It is not an unprimeable number, because it can be changed into a prime (11400713) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 28445 + ... + 28842.

It is an arithmetic number, because the mean of its divisors is an integer number (2864400).

Almost surely, 211400113 is an apocalyptic number.

It is an amenable number.

11400113 is a deficient number, since it is larger than the sum of its proper divisors (57487).

11400113 is an equidigital number, since it uses as much as digits as its factorization.

11400113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 57486.

The product of its (nonzero) digits is 12, while the sum is 11.

The square root of 11400113 is about 3376.4053370412. The cubic root of 11400113 is about 225.0624550902.

Adding to 11400113 its reverse (31100411), we get a palindrome (42500524).

The spelling of 11400113 in words is "eleven million, four hundred thousand, one hundred thirteen".

Divisors: 1 199 57287 11400113