1140041113133 has 16 divisors (see below), whose sum is σ = 1300034801520. Its totient is φ = 990383210496.

The previous prime is 1140041113111. The next prime is 1140041113241. The reversal of 1140041113133 is 3313111400411.

It can be written as a sum of positive squares in 8 ways, for example, as 137165048164 + 1002876064969 = 370358^2 + 1001437^2 .

It is a cyclic number.

It is not a de Polignac number, because 1140041113133 - 2¹² = 1140041109037 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1140041113099 and 1140041113108.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1140041113103) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3735941 + ... + 4029557.

It is an arithmetic number, because the mean of its divisors is an integer number (81252175095).

Almost surely, 2^{1140041113133} is an apocalyptic number.

1140041113133 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

1140041113133 is a deficient number, since it is larger than the sum of its proper divisors (159993688387).

1140041113133 is a wasteful number, since it uses less digits than its factorization.

1140041113133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 311216.

The product of its (nonzero) digits is 432, while the sum is 23.

Adding to 1140041113133 its reverse (3313111400411), we get a palindrome (4453152513544).

The spelling of 1140041113133 in words is "one trillion, one hundred forty billion, forty-one million, one hundred thirteen thousand, one hundred thirty-three".