Base | Representation |
---|---|
bin | 10000100101101111101… |
… | …111110000011001101011 |
3 | 11000222122102111120222102 |
4 | 100211233233300121223 |
5 | 122134301011422220 |
6 | 2231421101444015 |
7 | 145236165442514 |
oct | 20455757603153 |
9 | 4028572446872 |
10 | 1140041123435 |
11 | 3aa541547745 |
12 | 164b4557060b |
13 | 83675528816 |
14 | 3d26d2dba0b |
15 | 1e9c5dac775 |
hex | 1096fbf066b |
1140041123435 has 64 divisors (see below), whose sum is σ = 1497202237440. Its totient is φ = 829852600320.
The previous prime is 1140041123411. The next prime is 1140041123437. The reversal of 1140041123435 is 5343211400411.
It is not a de Polignac number, because 1140041123435 - 26 = 1140041123371 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1140041123398 and 1140041123407.
It is not an unprimeable number, because it can be changed into a prime (1140041123437) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 339397286 + ... + 339400644.
It is an arithmetic number, because the mean of its divisors is an integer number (23393784960).
Almost surely, 21140041123435 is an apocalyptic number.
1140041123435 is a deficient number, since it is larger than the sum of its proper divisors (357161114005).
1140041123435 is a wasteful number, since it uses less digits than its factorization.
1140041123435 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4076.
The product of its (nonzero) digits is 5760, while the sum is 29.
Adding to 1140041123435 its reverse (5343211400411), we get a palindrome (6483252523846).
The spelling of 1140041123435 in words is "one trillion, one hundred forty billion, forty-one million, one hundred twenty-three thousand, four hundred thirty-five".
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