Base | Representation |
---|---|
bin | 10101001111000110… |
… | …11110111010010010 |
3 | 1002102120001101210001 |
4 | 22213203132322102 |
5 | 141322131000224 |
6 | 5123151400214 |
7 | 552346111231 |
oct | 124743367222 |
9 | 32376041701 |
10 | 11401031314 |
11 | 4920648632 |
12 | 226222306a |
13 | 10c903a49a |
14 | 7a2262b18 |
15 | 46ada8544 |
hex | 2a78dee92 |
11401031314 has 4 divisors (see below), whose sum is σ = 17101546974. Its totient is φ = 5700515656.
The previous prime is 11401031287. The next prime is 11401031381. The reversal of 11401031314 is 41313010411.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 11156640625 + 244390689 = 105625^2 + 15633^2 .
It is a junction number, because it is equal to n+sod(n) for n = 11401031291 and 11401031300.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2850257827 + ... + 2850257830.
Almost surely, 211401031314 is an apocalyptic number.
11401031314 is a deficient number, since it is larger than the sum of its proper divisors (5700515660).
11401031314 is an equidigital number, since it uses as much as digits as its factorization.
11401031314 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5700515659.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 11401031314 its reverse (41313010411), we get a palindrome (52714041725).
The spelling of 11401031314 in words is "eleven billion, four hundred one million, thirty-one thousand, three hundred fourteen".
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