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11401044433 = 33134444243
BaseRepresentation
bin10101001111000111…
…00010000111010001
31002102120002001202221
422213203202013101
5141322131410213
65123151541041
7552346164412
oct124743420721
932376061687
1011401044433
114920657479
12226222a781
1310c904344c
147a2267809
1546adac38d
hex2a78e21d1

11401044433 has 4 divisors (see below), whose sum is σ = 11435489008. Its totient is φ = 11366599860.

The previous prime is 11401044397. The next prime is 11401044439. The reversal of 11401044433 is 33444010411.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11401044433 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11401044398 and 11401044407.

It is not an unprimeable number, because it can be changed into a prime (11401044439) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 17221791 + ... + 17222452.

It is an arithmetic number, because the mean of its divisors is an integer number (2858872252).

Almost surely, 211401044433 is an apocalyptic number.

It is an amenable number.

11401044433 is a deficient number, since it is larger than the sum of its proper divisors (34444575).

11401044433 is an equidigital number, since it uses as much as digits as its factorization.

11401044433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 34444574.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 11401044433 its reverse (33444010411), we get a palindrome (44845054844).

The spelling of 11401044433 in words is "eleven billion, four hundred one million, forty-four thousand, four hundred thirty-three".

Divisors: 1 331 34444243 11401044433