114010543104345 has 12 divisors (see below), whose sum is σ = 197618274714276. Its totient is φ = 60805622988960.

The previous prime is 114010543104343. The next prime is 114010543104391. The reversal of 114010543104345 is 543401345010411.

114010543104345 is a `hidden beast` number, since 1 + 1 + 4 + 0 + 1 + 0 + 543 + 104 + 3 + 4 + 5 = 666.

It can be written as a sum of positive squares in 2 ways, for example, as 11459497795344 + 102551045309001 = 3385188^2 + 10126749^2 .

It is not a de Polignac number, because 114010543104345 - 2¹ = 114010543104343 is a prime.

It is not an unprimeable number, because it can be changed into a prime (114010543104343) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 1266783812226 + ... + 1266783812315.

It is an arithmetic number, because the mean of its divisors is an integer number (16468189559523).

Almost surely, 2^{114010543104345} is an apocalyptic number.

114010543104345 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

It is an amenable number.

114010543104345 is a deficient number, since it is larger than the sum of its proper divisors (83607731609931).

114010543104345 is a wasteful number, since it uses less digits than its factorization.

114010543104345 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2533567624552 (or 2533567624549 counting only the distinct ones).

The product of its (nonzero) digits is 57600, while the sum is 36.

Adding to 114010543104345 its reverse (543401345010411), we get a palindrome (657411888114756).

The spelling of 114010543104345 in words is "one hundred fourteen trillion, ten billion, five hundred forty-three million, one hundred four thousand, three hundred forty-five".