Base | Representation |
---|---|
bin | 11001111011000100100101… |
… | …111011000010000101010111 |
3 | 112221200022010202221200021021 |
4 | 121323010211323002011113 |
5 | 104420422043013314333 |
6 | 1042251415341102011 |
7 | 33004663353446344 |
oct | 3173044573020527 |
9 | 487608122850237 |
10 | 114010543104343 |
11 | 33366666374136 |
12 | 10954010257907 |
13 | 4b801c0451c72 |
14 | 20221d55b97cb |
15 | d2aa210aa82d |
hex | 67b125ec2157 |
114010543104343 has 2 divisors, whose sum is σ = 114010543104344. Its totient is φ = 114010543104342.
The previous prime is 114010543104301. The next prime is 114010543104391. The reversal of 114010543104343 is 343401345010411.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 114010543104343 - 221 = 114010541007191 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 114010543104299 and 114010543104308.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (114010543107343) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57005271552171 + 57005271552172.
It is an arithmetic number, because the mean of its divisors is an integer number (57005271552172).
Almost surely, 2114010543104343 is an apocalyptic number.
114010543104343 is a deficient number, since it is larger than the sum of its proper divisors (1).
114010543104343 is an equidigital number, since it uses as much as digits as its factorization.
114010543104343 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 34560, while the sum is 34.
Adding to 114010543104343 its reverse (343401345010411), we get a palindrome (457411888114754).
The spelling of 114010543104343 in words is "one hundred fourteen trillion, ten billion, five hundred forty-three million, one hundred four thousand, three hundred forty-three".
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