114011430243311 has 4 divisors (see below), whose sum is σ = 114017838637824. Its totient is φ = 114005021848800.

The previous prime is 114011430243299. The next prime is 114011430243329. The reversal of 114011430243311 is 113342034110411.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 114011430243311 - 2⁴² = 109613383732207 is a prime.

It is a super-2 number, since 2×114011430243311² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (114011430203311) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3204170570 + ... + 3204206151.

It is an arithmetic number, because the mean of its divisors is an integer number (28504459659456).

Almost surely, 2^{114011430243311} is an apocalyptic number.

114011430243311 is a deficient number, since it is larger than the sum of its proper divisors (6408394513).

114011430243311 is an equidigital number, since it uses as much as digits as its factorization.

114011430243311 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6408394512.

The product of its (nonzero) digits is 3456, while the sum is 29.

Adding to 114011430243311 its reverse (113342034110411), we get a palindrome (227353464353722).

The spelling of 114011430243311 in words is "one hundred fourteen trillion, eleven billion, four hundred thirty million, two hundred forty-three thousand, three hundred eleven".