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1140121113 = 32411576931
BaseRepresentation
bin100001111110100…
…1101111000011001
32221110100011010220
41003331031320121
54313332333423
6305044430253
740152604155
oct10375157031
92843304126
101140121113
1153562895a
122799a8389
1315228a6a1
14ab5c4065
156a15d9e3
hex43f4de19

1140121113 has 8 divisors (see below), whose sum is σ = 1526470176. Its totient is φ = 756926400.

The previous prime is 1140121097. The next prime is 1140121141. The reversal of 1140121113 is 3111210411.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 1140121113 - 24 = 1140121097 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1140121092 and 1140121101.

It is not an unprimeable number, because it can be changed into a prime (1140121183) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 787743 + ... + 789188.

It is an arithmetic number, because the mean of its divisors is an integer number (190808772).

Almost surely, 21140121113 is an apocalyptic number.

It is an amenable number.

1140121113 is a deficient number, since it is larger than the sum of its proper divisors (386349063).

1140121113 is a wasteful number, since it uses less digits than its factorization.

1140121113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1577175.

The product of its (nonzero) digits is 24, while the sum is 15.

The square root of 1140121113 is about 33765.6795133757. The cubic root of 1140121113 is about 1044.6809196526.

Adding to 1140121113 its reverse (3111210411), we get a palindrome (4251331524).

The spelling of 1140121113 in words is "one billion, one hundred forty million, one hundred twenty-one thousand, one hundred thirteen".

Divisors: 1 3 241 723 1576931 4730793 380040371 1140121113