Base | Representation |
---|---|
bin | 10101001111001000… |
… | …01101000011001111 |
3 | 1002102120102000000122 |
4 | 22213210031003033 |
5 | 141322203022203 |
6 | 5123155415155 |
7 | 552350526224 |
oct | 124744150317 |
9 | 32376360018 |
10 | 11401220303 |
11 | 4920767620 |
12 | 22622b44bb |
13 | 10c90a5505 |
14 | 7a22b194b |
15 | 46ade4538 |
hex | 2a790d0cf |
11401220303 has 4 divisors (see below), whose sum is σ = 12437694888. Its totient is φ = 10364745720.
The previous prime is 11401220287. The next prime is 11401220353. The reversal of 11401220303 is 30302210411.
11401220303 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 11401220303 - 24 = 11401220287 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11401220353) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 518237276 + ... + 518237297.
It is an arithmetic number, because the mean of its divisors is an integer number (3109423722).
Almost surely, 211401220303 is an apocalyptic number.
11401220303 is a deficient number, since it is larger than the sum of its proper divisors (1036474585).
11401220303 is a wasteful number, since it uses less digits than its factorization.
11401220303 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1036474584.
The product of its (nonzero) digits is 144, while the sum is 17.
Adding to 11401220303 its reverse (30302210411), we get a palindrome (41703430714).
The spelling of 11401220303 in words is "eleven billion, four hundred one million, two hundred twenty thousand, three hundred three".
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