Base | Representation |
---|---|
bin | 10000100101110100101… |
… | …001010001111110000011 |
3 | 11000222212011011012111110 |
4 | 100211310221101332003 |
5 | 122134433031441003 |
6 | 2231433155214403 |
7 | 145241214152364 |
oct | 20456451217603 |
9 | 4028764135443 |
10 | 1140123312003 |
11 | 3aa583983185 |
12 | 164b68ba7403 |
13 | 83689574100 |
14 | 3d27a1b3b6b |
15 | 1e9cd1e4a03 |
hex | 10974a51f83 |
1140123312003 has 24 divisors (see below), whose sum is σ = 1646516821440. Its totient is φ = 701434637280.
The previous prime is 1140123311989. The next prime is 1140123312011. The reversal of 1140123312003 is 3002133210411.
It is not a de Polignac number, because 1140123312003 - 26 = 1140123311939 is a prime.
It is not an unprimeable number, because it can be changed into a prime (1140123312803) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 1706988 + ... + 2279046.
It is an arithmetic number, because the mean of its divisors is an integer number (68604867560).
Almost surely, 21140123312003 is an apocalyptic number.
1140123312003 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
1140123312003 is a deficient number, since it is larger than the sum of its proper divisors (506393509437).
1140123312003 is a wasteful number, since it uses less digits than its factorization.
1140123312003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 576019 (or 576006 counting only the distinct ones).
The product of its (nonzero) digits is 432, while the sum is 21.
Adding to 1140123312003 its reverse (3002133210411), we get a palindrome (4142256522414).
The spelling of 1140123312003 in words is "one trillion, one hundred forty billion, one hundred twenty-three million, three hundred twelve thousand, three".
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