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11401233303 = 34007948443
BaseRepresentation
bin10101001111001000…
…10000001110010111
31002102120102122212010
422213210100032113
5141322203431203
65123155555303
7552350612145
oct124744201627
932376378763
1011401233303
114920776369
1222622bbb33
1310c90ab3c5
147a22b6595
1546ade8303
hex2a7910397

11401233303 has 8 divisors (see below), whose sum is σ = 15205454208. Its totient is φ = 7598917304.

The previous prime is 11401233281. The next prime is 11401233313. The reversal of 11401233303 is 30333210411.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 11401233303 - 210 = 11401232279 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 11401233303.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11401233313) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 462201 + ... + 486242.

It is an arithmetic number, because the mean of its divisors is an integer number (1900681776).

Almost surely, 211401233303 is an apocalyptic number.

11401233303 is a deficient number, since it is larger than the sum of its proper divisors (3804220905).

11401233303 is an equidigital number, since it uses as much as digits as its factorization.

11401233303 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 952453.

The product of its (nonzero) digits is 648, while the sum is 21.

Adding to 11401233303 its reverse (30333210411), we get a palindrome (41734443714).

The spelling of 11401233303 in words is "eleven billion, four hundred one million, two hundred thirty-three thousand, three hundred three".

Divisors: 1 3 4007 12021 948443 2845329 3800411101 11401233303