Base | Representation |
---|---|
bin | 1010010111101000111110… |
… | …0010010100101011001011 |
3 | 1111100221121210211212021011 |
4 | 2211322033202110223023 |
5 | 2443244230320434201 |
6 | 40125355040224351 |
7 | 2254466431262653 |
oct | 245721742245313 |
9 | 44327553755234 |
10 | 11401251343051 |
11 | 36a6275175919 |
12 | 134178000b0b7 |
13 | 64919709236b |
14 | 2b5b759d1363 |
15 | 14b88cd81151 |
hex | a5e8f894acb |
11401251343051 has 16 divisors (see below), whose sum is σ = 11543308406784. Its totient is φ = 11260111593024.
The previous prime is 11401251343049. The next prime is 11401251343063. The reversal of 11401251343051 is 15034315210411.
It is a happy number.
It is a cyclic number.
It is not a de Polignac number, because 11401251343051 - 21 = 11401251343049 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11401251343081) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 48244360 + ... + 48480106.
It is an arithmetic number, because the mean of its divisors is an integer number (721456775424).
Almost surely, 211401251343051 is an apocalyptic number.
11401251343051 is a deficient number, since it is larger than the sum of its proper divisors (142057063733).
11401251343051 is a wasteful number, since it uses less digits than its factorization.
11401251343051 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 237690.
The product of its (nonzero) digits is 7200, while the sum is 31.
Adding to 11401251343051 its reverse (15034315210411), we get a palindrome (26435566553462).
The spelling of 11401251343051 in words is "eleven trillion, four hundred one billion, two hundred fifty-one million, three hundred forty-three thousand, fifty-one".
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