114012535403133 has 12 divisors (see below), whose sum is σ = 164729979219520. Its totient is φ = 75987492692616.

The previous prime is 114012535403101. The next prime is 114012535403177. The reversal of 114012535403133 is 331304535210411.

114012535403133 is a `hidden beast` number, since 1 + 1 + 4 + 0 + 1 + 2 + 53 + 540 + 31 + 33 = 666.

It is not a de Polignac number, because 114012535403133 - 2⁵ = 114012535403101 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (114012535403933) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 1738652293 + ... + 1738717866.

Almost surely, 2^{114012535403133} is an apocalyptic number.

It is an amenable number.

114012535403133 is a deficient number, since it is larger than the sum of its proper divisors (50717443816387).

114012535403133 is a wasteful number, since it uses less digits than its factorization.

114012535403133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3477373808 (or 3477373805 counting only the distinct ones).

The product of its (nonzero) digits is 64800, while the sum is 36.

The spelling of 114012535403133 in words is "one hundred fourteen trillion, twelve billion, five hundred thirty-five million, four hundred three thousand, one hundred thirty-three".