114013113 has 4 divisors (see below), whose sum is σ = 152017488. Its totient is φ = 76008740.

The previous prime is 114013111. The next prime is 114013153. The reversal of 114013113 is 311310411.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 114013113 - 2¹ = 114013111 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 114013092 and 114013101.

It is not an unprimeable number, because it can be changed into a prime (114013111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 19002183 + ... + 19002188.

It is an arithmetic number, because the mean of its divisors is an integer number (38004372).

Almost surely, 2^114013113 is an apocalyptic number.

It is an amenable number.

114013113 is a deficient number, since it is larger than the sum of its proper divisors (38004375).

114013113 is an equidigital number, since it uses as much as digits as its factorization.

114013113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 38004374.

The product of its (nonzero) digits is 36, while the sum is 15.

The square root of 114013113 is about 10677.6923068611. The cubic root of 114013113 is about 484.8993492203.

Adding to 114013113 its reverse (311310411), we get a palindrome (425323524).

The spelling of 114013113 in words is "one hundred fourteen million, thirteen thousand, one hundred thirteen".