114013153 has 2 divisors, whose sum is σ = 114013154. Its totient is φ = 114013152.

The previous prime is 114013111. The next prime is 114013157. The reversal of 114013153 is 351310411.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 60093504 + 53919649 = 7752^2 + 7343^2 .

It is an emirp because it is prime and its reverse (351310411) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 114013153 - 2²¹ = 111916001 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 114013153.

It is not a weakly prime, because it can be changed into another prime (114013157) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57006576 + 57006577.

It is an arithmetic number, because the mean of its divisors is an integer number (57006577).

Almost surely, 2^114013153 is an apocalyptic number.

It is an amenable number.

114013153 is a deficient number, since it is larger than the sum of its proper divisors (1).

114013153 is an equidigital number, since it uses as much as digits as its factorization.

114013153 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 180, while the sum is 19.

The square root of 114013153 is about 10677.6941799248. The cubic root of 114013153 is about 484.8994059271.

Adding to 114013153 its reverse (351310411), we get a palindrome (465323564).

The spelling of 114013153 in words is "one hundred fourteen million, thirteen thousand, one hundred fifty-three".