1140132211153 has 4 divisors (see below), whose sum is σ = 1227834688948. Its totient is φ = 1052429733360.

The previous prime is 1140132211129. The next prime is 1140132211171. The reversal of 1140132211153 is 3511122310411.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 502726377024 + 637405834129 = 709032^2 + 798377^2 .

It is a cyclic number.

It is not a de Polignac number, because 1140132211153 - 2¹³ = 1140132202961 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1140132214153) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 43851238878 + ... + 43851238903.

It is an arithmetic number, because the mean of its divisors is an integer number (306958672237).

Almost surely, 2^{1140132211153} is an apocalyptic number.

1140132211153 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

1140132211153 is a deficient number, since it is larger than the sum of its proper divisors (87702477795).

1140132211153 is an equidigital number, since it uses as much as digits as its factorization.

1140132211153 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 87702477794.

The product of its (nonzero) digits is 720, while the sum is 25.

Adding to 1140132211153 its reverse (3511122310411), we get a palindrome (4651254521564).

The spelling of 1140132211153 in words is "one trillion, one hundred forty billion, one hundred thirty-two million, two hundred eleven thousand, one hundred fifty-three".